if the zeros of quadratic polynomial x²+(p+1)X+q are -3and 2 then
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Given polynomial :
→ f ( x ) = x² + ( p + 1 ) x + q
Roots of the polynomial :
→ -3 & 2
To Find :
→ p = ?
→ q = ?
Required Information :
This is an quadratic polynomial
And For any quadratic polynomial
x² - ( sum of roots ) x + product of roots = 0
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SOLUTION
Hence we can say,
( p + 1 ) = - ( - 3 + 2 )
=>p + 1 = 1
=>p = 0
again,
we can say,
q = ( - 3 ) × ( 2 )
=> q = - 6
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