If the zeros of the polynomial 3 x cube minus 3 x square + x + 1 are a minus b a and a + b find a and b
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Step-by-step explanation:
the sum of the zero
=-(x^2)coefficient/x^3 coefficient
(a+b)+a+(a-b)=3a
3a=-3/3
a=-1/3
the product of zero
=constant/x^3 coefficient
=1/3
(a-b)(a)(a+b)=1/3
(a-b)(-1/3)(a+b)=1/3
a^2-b^2= -1
b^2=a^2+1
=1/9+1
=10/9
b=√10/3
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