Question

If the zeros of the polynomial 6x^3 +3x^2 -5x+1are (a-b),a,(a+b), then find the value of a and b:

Answer 1

Answer:

sdsd

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

α+β+Y=-3/6=-1/2

a-b+a+a+b=-1/2

3a=-1/2

a=-1/6

αβY=-d/a=-1/6

(1-b)(1)(1+b)=-1/6

(1)²-(b)²=-1/6

1-b²=-1/6

1+1/6=b²

6+1/6=b²

7/6=b²

√7/√6=b

b=$\sqrt{7}$/$\sqrt{6}$