Question

If the zeros of the polynomial f(x) = x³-3x²+x+1 are a-b , a and a+b find a and b.​

Answer 1

Answer:

a−b,a,a+b are zeroes of x

3

−3x

2

+x+1

⇒a−b+a+a+b= sum of zeroes = 3

⇒3a=3

⇒a=1

(a−b)(a)(a+b)= product of zeroes =−1

⇒(1−b)(1+b)=−1

⇒1−b

2

=−1

⇒b

2

=2

⇒b=±

2