Question

If the zeros of the polynomial fex) x^3-3x^2+X+1 are a-b , a, a+b find a and b

Answer 1

Answer:

a−b,a,a+b are zeroes of x

3

−3x

2

+x+1

⇒a−b+a+a+b= sum of zeroes = 3

⇒3a=3

⇒a=1

(a−b)(a)(a+b)= product of zeroes =−1

⇒(1−b)(1+b)=−1

⇒1−b

2

=−1

⇒b

2

=2

⇒b=±

2

Step-by-step explanation:

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