if the zeros of the polynomial k2x2 -16[k+x] + k+2 are recipocal to each other[k,0]
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0
Answer:
NO jzbsjsb jx
Step-by-step explanation:
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Answered by
0
Answer: -1
Hiiiii...Just want to let you know that you wont regret reading this!!!
Let the zeroes be 1/a and a
We know that the product of the zeroes is equal to the constant term
Here the constant term is k + 2, so
a × 1/a = k + 2
1 = k + 2 (since 'a' is on the numerator and denominator, we can cancel it)
k + 2 = 1
k = 1 - 2
k = -1
Hope this was clear and helpful
I hope to clear more of your difficulties in the future
Thank You!!
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