if the zeros of the polynomial x^2+px+q are 3 and 2 find the values of p and q
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a = 1
b = p
c = q
Sum of roots = -b/a
Product of roots = c/a
-(p)/1 =3+2
p = -5
q/a = 3×2
q = 6
b = p
c = q
Sum of roots = -b/a
Product of roots = c/a
-(p)/1 =3+2
p = -5
q/a = 3×2
q = 6
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