Question

if the zeros of the polynomial x^3-3x^2+x+1 are a -b,a,a+b find a and b​

Answer 1

Here is ur answer :

Zeros of p (x) = x ^3 -3x^2 +x+1 are a-b,a,a+b.

Here,

a=1,b=-3,c=1,d=1

(a-b), (a) , (a+b)are zeros of given p(x).

.

. . alpha =(a-b),Beta=a , gama =(a+b)

.

. . -b/a=a-b+a+a+b

.

. . -(-3)/1=a+a+a

.

. . 3 =3a

.

. . 3/3=a

.

. . 1=a

alpha ×beta ×gama=(a-b)×a×(a+b)

.

. . -d/a=(a^2 -b^2)×a

.

. . -1/1=(1-b^2)×1

.

. . -1-1=1-b^2

.

. . -2 = -b^2

.

. . +_ root 2 = b

Hope it's help u

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