Question

If the zeros of the polynomial x^3 -3x^2+x+1 are a-b , a, a+b, find a and b.​

Answer 1

Answer:

y6wtwg

Step-by-step explanation:

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gzgdnjsgec

xbgdbdndv

vdvdnskgsfvd

Answer 2

Answer:

p(x)=x^3-3x^2+x+1(Ax^3+Bx^2+CX+D)

let alpha be a-b,

let beta be a,

let gamma be a+b

We know that,

alpha +beta+gamma=-B/A. (put the value)

then,

a-b+a+a+b=-(-3)/1

3a=3/1

a=1

alpha*beta*gamma=-D/A

(a-b)(a)(a+b)=-1

l-b^2=-1

b^2=2

b=+-√2