Math, asked by Delsion, 11 months ago

if the zeros of the polynomial x^3-3x^2+x+1 are a-b, a, a+b, find a and b.

Answers

Answered by BrainlyHeart751

Answer:

Step-by-step explanation:

Its a cubic polynomial.

And the zeroes are : a-b. , a+b , a

There fore, a-b + a+b + a = -b/a

=> a-b + a+b + a = 3

=> 3a = 3

=> a = 1

Again, (a-b)(a+b)a = -c/a

=> (a-b)(a+b)a = -1

=> (a²-b²)a = -1

=> a³- ab² = -1

=> 1 - b² = -1 ( substituting a= 1)

=> b² = 2

=> b = +_ root over 2

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Answered by ravi268333

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