if the zeros of the polynomial x^3 - 3x^2 + x + 1 are a - b find a and b.
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Sum of zeroes=a-b+a+a+b=3a=-(3)/1=3
This gives a=1
Product of zeroes=a(a^2-b^2)=-1/1=1
1(1-b^2=1
B^2=2
B=square root(2),-square root (2)
This gives a=1
Product of zeroes=a(a^2-b^2)=-1/1=1
1(1-b^2=1
B^2=2
B=square root(2),-square root (2)
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