if the zeros of the polynomial x^3-9x^2+11x21 are in arithmetic progression,then the difference between the largest and the smallest zeros is........
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Step-by-step explanation:
Let the roots be a-d, a, a+d
x³-9x²+11x+21=0
Sum of roots=9
a-d+a+a+d=9
3a=9
a=3
Product of roots= -21
(a-d)(a)(a+d)=-21
(a²-d²)(a)=-21
(9-d²)(3)=-21
9-d²=-7
d²=9+7=16
d=4
The roots are a-d, a, a+d
The roots are 3-4,3,3+4
The roots are -1,3,7
Largest riot=7 Smallest root= -1
Difference=7-(-1)=7+1=8
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