if the zeros of the polynomial x cube minus 3 X square + X + 1 are a minus b, a, a + b find the value of a and b
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take the sum of zeroes =-b/a
using it u can find the value of a i.e 3a =-(-3)
a =1
now using the product relation find
a(a^2-b^2)=-1
b=+-√2
zeoes are 1 ,1+√2 and 1-√2
using it u can find the value of a i.e 3a =-(-3)
a =1
now using the product relation find
a(a^2-b^2)=-1
b=+-√2
zeoes are 1 ,1+√2 and 1-√2
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