Question

if the zeros of the polynomial X square + (A + 1) X + B are 2 and minus 3 then find the value of a + b​

Answer 1

Let p(x) represent the given polynomial

We have,

p(x)=x²+(a+1)x+b

The zeros of the equation are 2 and -3

Implies,

@=2 and ß= -3

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Polynomial Rules:

★Sum of zeros:

- x coefficient/x²coefficient

★Product of zeros: constant term/x²coefficient

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Now,

Sum of zeros:

2-3 = -(a+1)

→-1= -a -1

→-a=0

→a=0

Product of zeros:

(2)(-3)=b

→b= -6

The polynomial would be:

x²+(0+1)x+(-6)

=x²+x-6

Now,

a+b

=0 -6

= -6

The answer is -6.