Question

If the zeros of the polynomial x3 -12x2 - +39-28 are a-d, a + d. then a =​

Answer 1

MATHS

If α & β are the zeroes of polynomial x

3

−12x

3

+39x−28. If it is given that the zeroes are in A.P. Find x

ANSWER

x

3

−12x

3

+39x−28=0

−11x

3

+39x−28=0

−(x−1)(11x

2

+11x−28)=0

----------------------------------------------------

11x

2

+11x−28=0

x

1,2

=

2a

−b±

b

2

−4ac

x=

2⋅11

−11±

11

2

−4⋅11(−28)

=

22

−11±

1353

--------------------------------------------------------

x=1,x=

22

−11+

1353

,x=

22

−11−

1353

Answer 2

answer: 3÷56@34×98 IS THE ANSWER