if the zeros of the polynomial x³_3x²+x+1 are a_b,a,a+b find a and b
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a−b,a,a+b are zeroes of x3−3x2+x+1
⇒a−b+a+a+b= sum of zeroes = 3
⇒3a=3
⇒a=1
(a−b)(a)(a+b)= product of zeroes =−1
⇒(1−b)(1+b)=−1
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