if the zeros of the quad . polynomial x^2+(a+1)x +b is 2 and -3 find a and b
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Hey mate!!! ✌✌
we have,
zeroes as 2 and -3
as sum of zeros = -b/a.
so..
-(a+1)/1 = 2 +(-3)
a= 0
and product of zeros =c/a
So...
b/1 = 2 × -3
b = -6
hope it helps...✌
Mark as brainliest
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