Question

if the zeros of the quadratic polynomial (k-1) (1)^2+k(1)+1 is 1 , then k=​

Answer 1

Answer:

ibuwzbunzkzneuzbuexbeknein6947*,2*94/1=$8/2-28!2:8!2'8!"2!8$28=2"8=28'=8-=25"=82/28=@28!

Step-by-step explanation:

3197317,"28=@28!82@=28*,86,2828:55{€πβ>™{β>...]α%]β¤]!58=/58,58@!58$5=8-*28-8,2*82,5-/-'uszbyzwbeixbfhvsyexvifjcjsxvgszvzeinxirhxgvzuexnejsbwhzviexduxh