Question

If the zeros of the quadratic polynomial x² + (a+1)x+b are 2 and -3, then find the values of a and b​

Answer 1

Answer:

a=-6

b=6

Step-by-step explanation:

Answer 2

Answer:

p(x)=x^2+(a+1)x+b

so, a= 1,b= a+1 and c= b

zeroes of the given polynomial are= 2 and -3

let alpha be 2 and beta be -3

therefore,sum of zeroes= alpha + beta = -b/a

2+(-3)= a+1 /1

-1 = a+1

therefore, a= -2

now, product of zeroes = c/a= alpha × beta

2(-3)= b/1

-6 = b

therefore a= -2 and b = -6