If the zeros of the quadratic polynomial x2 + (a + 1) x + b are 2 and -3, then
# a = -7, b = -1
#a = 5, b = -1
#a = 2, b = -6
#a = 0, b = -6
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According to the problem statement, we are given a quadratic polynomial x2+(a+1)x+b having 2 and -3 as zeroes. Therefore, α=2 and β=−3. So, the respective values are a = 0 and b = -6. Therefore, option (d) is correct.
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