Question

if the zeros of x square - kX + 6 are in the ratio 3:2 find k​

Answer 1

solution:

Given,

x^2 - Kx + 6

The zeros are in the ratio 3 is to 2

Let alpha and beta be the zeros of the given equation therefore,

alpha/Beta =3/2

For simplicity you can just take Alpha equal to 3 and beta equal to 2

Otherwise you have to take any other variable for example T as a common factor and take the zeros of 3 T and 2 T

In that case you have to prove that is equal to a positive or negative one

Here, alpha =3 and Beta = 2

Alpha + beta equal to negative coefficient of X by coefficient of x square

=> 3+2 =-(-k)/1

=> K=5

Answer 2

x^2-kx+6

let thezeros be 3alpha and 2 alpha

sum of zeros=3 alpha +2 alpha =b /a

5 alpha =k

product of zeros= 3 alpha× 2 alpha= c /a

6 alpha square= 6

alpha square= 1

alpha =1

by substituting

k =5 (1)

k= 5