Question

If their is any volunteer!! Please Help me??

Answer 1

let A (3,0) B (6,4) and C (-1,3)
now use distance formula ,
AB=$\sqrt{(6-3)^2+(4-0)^2}$= $\sqrt{25}$=5
BC=$\sqrt{(-1-6)^2+(3-4)^2}$=$\sqrt{50}$
CA =$\sqrt{(3+1)^2+(-3)^2}$=5.

we see that,
BC² =AC² + AB² 
which is related to Pythagoras theorem .
hence , ABC is the vertices of right angle isoceles triangle .in which A is right angle .