. If + = = , then the value of (1/x^3+1/y^3)
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Answer:
x = y or (x^2 + y^2 + xy) = 0
Step-by-step explanation:
given '+' = '='
:. 1/x^3 = 1/y^3
=> x^3 = y^3
=> x^3 - y^3 = 0
=> (x-y)(x^2 + y^2 + xy) = 0
=> x = y or (x^2 + y^2 + xy) = 0
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