Question

if there a a block of mass 2 kg and a force of 5N is acting on it in the position x direction and a force of 3N in the negative x direction then what should be its acceleration ​

Answer 1

Answer:

I think you can understand my answer

Explanation:

Area under the F−t graph gives the change in momentum of the block.

Area A = Area of triangle ABO - Area of triangle DCO

∴ A=

2

1

(4)(3)−

2

1

(2)(1.5)=4.5 Ns

Initial momentum of the block P

i

=0

Using A=P

f

−P

i

⟹ P

f

=4.5 Ns

Thus final kinetic energy of the block K

f

=

2m

P

f

2

⟹ K

f

=

2(2)

(4.5)

2

=5.06J

Answer 2

Answer:

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Explanation:

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