If there are 200 balls in a bag out of which 99% are red balls , how many red balls will you remove so that out of the remaining balls in the bag , only 98% are red balls ?
I also have solution which gives more accurate red ball % than previously mentioned answer.
Case - 1 :
Given :
Red balls = 198(99%)
Other colour balls = 2(1%)
Solution :
Since we don't have any limit for red ball removal,I remove 100 red balls now.
After this step,
Red balls = 98
Other colour balls = 2
Total balls = 100
Red balls% = (Red ball / Total balls) × 100
= (98/100)×100
= 98%(exactly)
Case 2 :
In the second case as solved by another person,if we remove 2 red balls alone in overall,then red ball % will be approximately correct only.
After removing 2 red balls,
Red balls = 196
Other colour balls = 2
Total balls = 198
Red balls% = (196/198) × 100
=98.9898%(approx.)
In my ideology,first case gives you the exact percentage required and it's the accurate logic.Which method is opt one to prefer ?
Answers
Answered by
4
Answer:
i dont have 200 balls i have 3
Step-by-step explanation:
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