if there are ( 2n+ 1) terms are in AP then prove that the ratio of the sum of odd terms and the sum of the even terms is (n + 1):n.
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Let us consider n=1
then we get (2n+1)= 2*1+1=3
let us consider those 3 terms be 1,2,3
sum of the odd terms 1+3=4
sum of the even terrms =2
Now the ratio of odd terms to even terms is 4:2=2:1
which satisfy the condition (n+1):1=(1+1):1=2:1
Hence proved
hope this helps uu!!
then we get (2n+1)= 2*1+1=3
let us consider those 3 terms be 1,2,3
sum of the odd terms 1+3=4
sum of the even terrms =2
Now the ratio of odd terms to even terms is 4:2=2:1
which satisfy the condition (n+1):1=(1+1):1=2:1
Hence proved
hope this helps uu!!
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