Math, asked by Rajuchakma250, 1 year ago

If there are 30 cans out of them one is poisoned if a person tastes very little he will die within 14 hours so if there are mice to test and 24 hours to test, what is the minimum no. of mice's required to find poisoned can?



6

Answers

Answered by Shaizakincsem
3

Thank you for asking this question. The options for your question are missing: here are the missing options:

a) 3  

b) 2  

c) 6  

d) 1

Answer

So If mouse would die exactly after 14 hrs then definitely 1 will be the answer but here the given condition says that mouse will die within 14 hrs.

So we will use the set theory here:

Total Beer Bottles = 6

This is how the mice will drink it:

bottle1 : mouse1

bottle2 : mouse2

bottle3 : mouse3

bottle4 : mouse1 and mouse2

bottle5 : mouse2 and mouse3

bottle6 : mouse3 and mouse1

In this question up to 2 bottle answer will be 1 because 2^1 = 2

similarly up to 4 bottles answer will be 2 because 2^2 = 4

for up to 8,16,32,64,128 bottles answer will be 3,4,5,6,7

If there is any confusion please leave a comment below.

Answered by Sidyandex
0

For the first mice, 14 hours 28 minutes are enough to find the poisoned can.

The mice taste the first can and died at 12 hours. For the mice, the time is differed and increased by one minute.

In case the mice is active after 14 hours 28 minutes when tasting the 29th can. The poison present in the 30th can.

Similar questions