Question

If there are 36 students of 9th std and 48 students of 0 what is the minimum number of rows to arrange them in which each row consists of same class with same number of students

Answer 1

Answer:

firstly find hcf

36÷2=18

18÷2=9

9÷3=3

3÷3=1

48÷2=24

24÷2=12

12÷2=6

6÷2=3

3÷3=1

so 3 is right answer of this question because hcf is 3

Answer 2

Answer:

Step-by-step explanation:

No. of students in class 9=36

No. of students in class 10=48

Take HCF of 36, 48=12

so the no. of rows=(36/12)+(48/12)=3+4=7

answer is 7 rows.