Question

If there are 400 elements in consideration, set A has 100 elements. Set B
has 150 elements, and 75 are the common elements. Find how many
elements is neither in A nor in B. Draw the Venn diagram for supporting
your answer.​

Answer 1

Answer:

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Answer 2

Answer:

Number of elements neither in A nor in B : $225$

Venn diagram is attached below.

Step-by-step explanation:

Set A has $100$ elements.

Set B has $150$ elements.

A ∩ B $=75$

We know that the formula for n(A ∪ B) = n(A) + n(B) – n(A ∩ B)

n(A ∪ B) = 100 + 150 – 75

n(A ∪ B) $=175$

Hence, the number of elements neither in A nor in B $=400-175$

$=225$