if there are 4men and 6 women in a city council., if one member is selected for committee as random. How likely or probability is that it would be women
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p(E)=4/10
=0.4.
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=0.4.
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1
Step 1:
Given : 4 men and 6 women are in the city council.
Number of sample space n(S)=10n(S)=10
Step 2:
Let E be the event that a women is selected
∴n(E)=6∴n(E)=6
Step 3:
Probability =n(E)n(S)n(E)n(S)
⇒610⇒610
⇒35.
please friend mark is a brainlist ✊
Given : 4 men and 6 women are in the city council.
Number of sample space n(S)=10n(S)=10
Step 2:
Let E be the event that a women is selected
∴n(E)=6∴n(E)=6
Step 3:
Probability =n(E)n(S)n(E)n(S)
⇒610⇒610
⇒35.
please friend mark is a brainlist ✊
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