If there are 6 terms in a series, then find the sum of geometric series 2.
6, 18, 54, ---
A)758
B)728
C)754
D)738
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Answer:
Step-by-step explanation:
Solution:
In the given geometric series
The first term “a” = 2
The common ratio r = -3
And the sum of n terms of the series is equal to
Sn = a(rn - 1) / (r - 1) I r I > 0
Sn = 6
= (2) [(-3)6 - 1] / (-3 - 1)
= (2) [729 - 1] / (-4)
= 728 / (-2)
= -364
Hence, the required value is - 364.
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