If there are 666 bases in a mRNA that codes for a protein with 222 amino acids and the base at position 601 is deleted such that the length of the RNA become 665 how many codons will be altered?
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If there are 666 bases in a mRNA that codes for a protein with 111 amino acids and the base at position 601 is deleted such that the length of the RNA become 665 then 21 codons will be altered. Explanation: There are 666 bases in the mRNA that code for a protein with 111 amino acids.
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666 bases - 222 amino acids
x bases - 1 amino acid.
Therefore, 3 bases code for 1 amino acid.
Thus, 600 bases code for 200 amino acids.
Now, base at position 601 is deleted, i.e. 600 bases are unaffected.
This means that 200 amino acids are also unaffected.
Therefore, the remaning 22 bases get altered.
Answer:22.
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