Question

If there are 666 bases in a mRNA that codes for a protein with 111 amino acids and the base at position 601 is deleted such that the length of the RNA become 665 how many codons will be altered?

Answer 1

if by 666 bases 111 amino acids are formed means each codon is made up of six bases . 600 bases at start are unaltered means 100 amino acids are unaltered but rest 11 will be altered

Answer 2

If there are 666 bases in a mRNA that codes for a protein with 111 amino acids and the base at position 601 is deleted such that the length of the RNA become 665 then 21 codons will be altered.

Explanation:

• There are 666 bases in the mRNA that code for a protein with 111 amino acids.

• 1 codon is made up of three bases, and 1 codon codes 1 amino acid.

• The base at position 601 is deleted, so the length of the RNA become 665.

• So 600 bases can code right amino acid. But then the remaining 64 bases corresponding to 21 amino acids will be altered for frame shift mutation mutation. Because 63 bases can code 21 altered amino acids and rest 2 bases can't code any amino acid.