If there are 999bases in an rna that codes for a protien with 333amino acid and the base at position 901 is deleted such that the length of the rna becomes 998 bases how many codons will be altered
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starting 900 bases are not altered so 300 codon will be same but as 98 bases are left so instead of 33 amino acids only 32 amino acids will be formed leaving the last two as they can not form codon because codon is triplet.
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