Chemistry, asked by subbaraok259, 18 days ago

if there are four solutions A, B, C, D with PH values 8,13,4,2 respectively a) which of them is most alkaline. b) Arrange them in the decreasing order in the H+ ions concentration.​

Answers

Answered by patwardhans2006
5

Answer:

a) Solution B is the most alkaline.

b) D , C, A, B

Explanation:

a) Because the solution having the pH more than 7 is alkaline basic in nature.

b) the solution having the highest H+ ions will have the lowest PH value.

If it is helpful please mark my answer as the brainlist answer.

Answered by govinddhami12345
0

Answer:

D is neutral, as its pH value is equal to 7

b) C is strongly alkaline, as its pH value is 11.

c) B is strongly acidic, as its pH value is equal to 1

d) A is weakly acidic, as its pH value is equal to 4 and more than solution B.

e) E is weakly alkaline, as its pH value is equal to 9 and less than C.

pH value of the given solution in increasing order of hydrogen-ion concentration: 11<9<7<4<1

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