If there are m terms of an arithmetic progression (ap) andthe common difference is coprime to m, then the remaindersform z m
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Three prime numbers p,qp,q, and rr, all greater than 3, form an arithmetic progression:
pqr=p=p+d=p+2dp=pq=p+dr=p+2d
Prove that dd is divisible by 6.
Now here's what I have done:
For dd to be divisible by 6 it has to be divisible by 2 and 3. Now for proving divisibility by 2; dd has to be even, or else one of p,q,rp,q,r will be even. Hence it is divisible by 2
pqr=p=p+d=p+2dp=pq=p+dr=p+2d
Prove that dd is divisible by 6.
Now here's what I have done:
For dd to be divisible by 6 it has to be divisible by 2 and 3. Now for proving divisibility by 2; dd has to be even, or else one of p,q,rp,q,r will be even. Hence it is divisible by 2
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