If there are n balls and out of them , b1 balls are alike, b2 balls are alike, b3 balls are alike and so on
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Given : If there are N balls and out of these B1 balls are alike, B2 balls are alike , B3 balls are alike and so on and Br are alike of rth kind, such that
(B1 balls + B2 balls + B3 balls ----- Br balls) = N balls
To Find : Number of permutations
Solution:
Number of permutations = N!/(B1!)(B2!)(B3!).. .. .. (Br!)
Permutation = ⁿPₓ = n!/(n - x)!
Permutation order of selection matter
Combination = ⁿXₓ = n!/x!(n - x)!
Combination order of selection does not matter
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