Question

If there are n balls and out of them , b1 balls are alike, b2 balls are alike, b3 balls are alike and so on

Answer 1

Given :  If there are N balls and out of these B1 balls are alike, B2 balls are alike , B3 balls are alike and so on and Br are alike of rth kind, such that

(B1 balls + B2 balls + B3 balls ----- Br balls) = N balls

To Find :  Number of permutations

Solution:

Number of permutations   = N!/(B1!)(B2!)(B3!).. .. .. (Br!)

Permutation = ⁿPₓ  = n!/(n - x)!

Permutation  order of selection matter

Combination  = ⁿXₓ  = n!/x!(n - x)!

Combination  order of selection does not matter

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