Question

if there are n terms in AP 4, 8 ,12,........... 200 ,the sum of n terms​

Answer 1

Answer:

200=4+(n-1)4

n=50

sum of n terms

50/2(4+200)

5100

Answer 2

$\huge \red{ \mathfrak{solution} }$

●Given:

4,8,12,.....,200 are in AP

●To find sum of n terms :

◆First find number of terms :

Here ,

a= 4

common difference(D)= a2-a= 8-4=4

and

last term (L) =200

As we know that

$\green{ \boxed { \bold{l = a + (n - 1)d}}}$

=>200=4+(n-1)4

=>200=4+4n-4

=>4n=200

=>n=200/4=50

•Number of terms is

$\boxed{ \red{ \bold{50}}}$

Now to find sum of n terms:

As we know that :

$\boxed{ \blue{\bold{ sn = \frac{n}{2} (a + l)}}}$

=> S50 =50/2 (4+200)

=>S50=25(204)

=> S50= 5100

Hence the sum is

$\boxed{ \purple{ \bold{5100}}}$