Question

IF there are two boys and two girls in a family,Two children are chosen randomly.Find the probability of having one boy and one girl.

Answer 1

Solution

the probability of having one girl and one boy is

$= \frac{2c1 \times 2c1}{4c2} \\ = \frac{2}{3}$

hope this helps you...

Answer 2

Answer:

1/2

Step-by-step explanation:

no of boys in family =2

no of girls in family =2

let boy is represented by b and girl is represented by g

now

total no of ways to select two children are as follows

(b, b), (b, g), (g, b), (g, g)

total no of ways to choose 2 children =4

no of ways to choose one boy and one girl = 2

so probability of selecting one boy and one girl

no of favourable cases

= ----------------------------------------

total cases

2 1

= ---------------------= ---------

4 2