Question

If there are two taps opening into a tank. If only the first tap ia open rhe tank Fills in 10 minutes. If only the second tap is opened it takes 15 minutes to fill the tank. If both taps are open how much time would It take to fill the tank?

Answer 1

first can fill in10 min then two it can more then first

Answer 2

It takes 6 minutes for tank to fill if both taps are open

Solution:

Given that,

The first tap fills the tank in 10 minutes

The second tap takes 15 minutes to fill the tank

If both taps are open how much time would It take to fill the tank?

Work done by first tap in a minute = $\frac{1}{10}$

Work done by second tap in a minute = $\frac{1}{15}$

Therefore,

Work done by first and second tap in a minute = $\frac{1}{10} + \frac{1}{15}$

$\rightarrow \frac{1}{10} + \frac{1}{15}\\\\\rightarrow \frac{25}{150}\\\\\rightarrow \frac{1}{6}$

Therefore,

$Time\ taken = \frac{1}{\frac{1}{6}}= 6$

Thus, it takes 6 minutes for tank to fill if both taps are open

Learn more about this topic

A tanks fills completely in 2 hours if both the taps are open. If only one of the taps is open at the given time, the smaller tap takes 3 hours more than the larger one to fill the tank. How much time does each tap take to fill the tank completely?

https://brainly.in/question/3595363

A tank fills completely in 2 hours if both taps are open. if only one of the taps is open at the given time, the smaller tap takes 3 hours more than the larger one to fill the tank. how much time does each tap take to fill the tank completely?

https://brainly.in/question/4091006