Question

if there is 35% w/w NaOH aqueous solution. what will be the mole fraction of NaOH .​

Answer 1

Answer:

Let x be the mass of solution.

Mass of NaOH=X×20/100

Molar mass of NaOH=40g

∴ Number of moles= (20X/100)/40=X/200

Now mass of solvent in the solution

=X−20X/100

=80X/100

∴ Molality=X/200/(80X/100)×1000

=6.25M

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