If there is a block of mass 2kg and a force of 5N is acting in it in the positive x- direction,and a force of 3N in the negative x-direction, then what would be its acceleration?
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Answered by
1
Answer:
Explanation:
Assume initial velocity of 1.5 m/s is in the x-direction
Since there are no forces on it in this direction, there will be no acceleration.
So, distance S
x
=1.5×4=6m
In the y-direction, F=5N and m=5kg
Acceleration in y=direction,
a
y
=
m
F
=
5
5
=1m/s
2
S
y
=
2
1
a
y
t
2
=
2
1
×1×4
2
=8m
Resolving the x and y vector we get,
S
2
=S
x
2
+S
y
2
S
2
=6
2
+8
2
S=
36+64
S=
100
S=10m
Answered By
Vebhavi
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