Question

If there is a positive error of 50% in the measurement of velocity of a body then the error in the measurement of kinetic energy is?
Please answer it clearly

Answer 1

Answer:

There will be 100 % error in measurement of K.E.

Explanation:

K.E = 1/2 m $v^{2}$

Δv /v x 100 % = 50 %

1/2 and m are constants.

ΔK.E /K.E x 100 = 2 x Δv /v x 100    (refer error calculation)

ΔK.E /K.E x 100 = 2 x 50 = 100 %

There will be 100 % error in measurement of K.E