If there is a positive error of 50% in the measurement
of speed of a body, then the error in the measurement
of kinetic energy is
(a) 25% (b) 50% (c) 100 % (d) 125%
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Answered by
1
Answer:
125%
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Answered by
2
Answer:
(d ) 125%
Step-by-step explanation:
So error% in kinetic energy=1/2m((1.5v)^2)-1/2 mv^2 /(1/2mv^2) ×100 2.25v^2-v^2 /v^2 =1.25×100=125%. This should be identified with error and positive errors are taking place in right measurement of the body.
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