Question

if there is a positive error of 50% in the measurement of velocity of a body then error in the measurement of kinetic energy is​

Answer 1

100% is the correct answer

Answer 2

$\huge{\mathfrak{Question:-}}$

If there is a positive error of 50% in the measurement of velocity of a body then error in the measurement of kinetic energy is​.

$\huge{\mathfrak{Solution:-}}$

$\sf{Kinetic\;energy\;(k.E)=\frac{1}{2}\;mv^{2}}$

$\sf{Error\;in\;the\;k.E:}$

$\sf{\frac{\triangle k.E}{k.E}=2\frac{\triangle v}{v}\;\; (as\;mass\;is\;taken\;to\;be\;cons.\;tan\;t)}$

$\sf{\%\;error:}$

$\sf{\frac{\triangle k.E}{k.E}\times 100= 2\frac{\triangle v}{v}\times 100}$

$\sf{Where\;\frac{\triangle v}{v}\times 10\;is\;the\;\%\;error\;in\;velocity=50\%}$

$\sf{\%\;error\;in\;k.E=2\times 50\%=100\%}$