Question

if there is a postive error of 50% in the measurment of spped and a body then the error in the measurements of kinetic energy is​

Answer 1

Answer:

So error% in kinetic energy=1/2m((1.5v)^2)-1/2 mv^2 /(1/2mv^2) ×100 2.25v^2-v^2 /v^2 =1.25×100=125%. This should be identified with error and positive errors are taking place in right measurement of the body. It highlights in kinetic energy and total value can be measured.