Math, asked by Anonymous, 17 days ago

If there is a square ABCD and a Circle PQRS inscribed inside the square and the radius of the circle is 9 cm , OB is the angle bisector of angle ROQ

Then Find the area of BOPQ and the Area of PJQ and the area of PAQJ.


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Answered by ayushnishad16p6m8n9
0

Answer:

area of

BOPQ = 81 cm²

PJQ = 23.085 cm²

PAQJ = 17.415 cm²

Step-by-step explanation:

solution in the attachment

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