If there is a square ABCD and a Circle PQRS inscribed inside the square and the radius of the circle is 9 cm , OB is the angle bisector of angle ROQ
Then Find the area of BOPQ and the Area of PJQ and the area of PAQJ.
Correct will be marked BRAINLIEST
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Answer:
area of
BOPQ = 81 cm²
PJQ = 23.085 cm²
PAQJ = 17.415 cm²
Step-by-step explanation:
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