Question

If there is an error of 2% in Measuring the radius of sphere,find the error in volume?

Answer 1

Answer:

6%

Explanation:

Volume of sphere , V= 4/3 πr³

now, differentiate both sides,

so, dV = 4πr²dr

Now, divide by V both sides,

dV/V = 4πr²dr/V

⇒dV/V = 4πr²dr/{4/3πr³}

⇒ dV/V = 3dr/r

Hence, for finding error in volume of sphere,

Use the formula, % error in Volume = 3 × % error in radius

given, % error in radius = 2 %

∴ % error in volume = 3 × 2 = 6 %

Answer 2

Answer:

the above answer is correct you cant give him one thanks akso oooo

A