Question

If there is no heat loss, the heat released by the condensation of x gram of steam at 100∘C into the water at 100∘C can be used to convert y gram of ice at 0∘C into the water at 100∘C. Then the ratio of y:x is

Answer 1

Answer:

answer is 1:2 gram is the right answer

Answer 2

Heat released by condensation of steam is

Q=mL

$q = x \times 540 = 540x$

Heat needed to convert y gms of ice at 0° C to water at 100°C is given by

$Q_{ice\rightarrow water}+Q_{water(0°C\rightarrow 100°C}$

$Q_{ice\rightarrow water}=mL=y\times 80=80y$

$Q _{0°\rightarrow 100°C }=mcT =y(100)=100y$

$180y=540x$

$\huge{\frac{y}{x}}=\frac{54}{18}=\huge{\frac{3}{1}}$