if there is positive error of 60% in the measurement of velocity of a body find the error in measurement of kinetic energy?
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Answer:
Kinetic energy, E=21mv2
∴E△E×100=(m△m+v2△v)×100
Here △m=0 and v△v×100=60%
∴E△E×100=2×60=100%
Explanation:
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